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6x^2-37x+56=0
a = 6; b = -37; c = +56;
Δ = b2-4ac
Δ = -372-4·6·56
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-5}{2*6}=\frac{32}{12} =2+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+5}{2*6}=\frac{42}{12} =3+1/2 $
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